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9600=6x^2
We move all terms to the left:
9600-(6x^2)=0
a = -6; b = 0; c = +9600;
Δ = b2-4ac
Δ = 02-4·(-6)·9600
Δ = 230400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{230400}=480$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-480}{2*-6}=\frac{-480}{-12} =+40 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+480}{2*-6}=\frac{480}{-12} =-40 $
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